Question 960666
{{{(x-h)^2+(y-k)^2=r^2}}}

so, a circle that has an equation of {{{(x+7)^2+y^2=49}}}, has the center ({{{h}}},{{{k}}})=({{{-7}}},{{{0}}}) and radius {{{r=7}}} 


{{{drawing( 600, 600, -15, 10, -10, 10, 
circle(-7,0,.2),locate(-7,0.6,C(-7,0)),circle(-7,0,7),
graph( 600, 600, -15, 10, -10, 10,0)) }}}