Question 960574
Probility(Pr)
i) Pr (both contracts occur) = (4/10) * (1/10) = 4/100 = .04
ii) Pr(neither contract occurs) = (6/10) * (9/10) = 54/100 = .54
note if Pr of getting contract is .4, then not getting contract is 1 - .4 = .6
iii) Pr (at least one contract occurs) = .4 + .1 = .5