Question 960117
{{{x+y=2 }}}
{{{x=2-y}}}
{{{x^2=4-4y+y^2}}}
Substitute,
{{{3(4-4y+y^2)+4(2-y)y+y^2=6}}}
{{{12-12y+3y^2+8y-4y^2+y^2=6}}}
{{{12-4y=6}}}
{{{-4y=-6}}}
{{{y=6/4}}}
{{{highlight(y=3/2)}}}
Then,
{{{x=2-(3/2)}}}
{{{x=4/2-3/2}}}
{{{highlight(x=1/2)}}}