Question 960365
0.2 cot^2(A) - 0.5 cot(A) = 1.2
Sub x for cot(A)
0.2x^2 - 0.5x = 1.2
2x^2 - 5x - 12 = 0
(2x + 3)*(x - 4) = 0
x = 4 --> cot(A) = 4
A =~ 14.04 degs, 194.04 degs
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x = -3/2
A =~ 146.31 deg, 326.31 degs,