Question 960223
Write as a single logarithm:

{{{log(6,2) - log(6,4) - 2log(6,3) }}}

I stink at logs and I ended up with  {{{log(6,2/36)}}}
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{{{log(6,2) - log(6,4) - 2log(6,3)}}}
= {{{log(6,2) - log(6,4) - log(6,9) }}}
= {{{log(6,2/(4*9))}}}
= {{{log(6,2/36)}}}
= {{{log(6,1/18)}}}
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And then it asks me to solve
{{{log(6,2) - log(6,4) - 2log(6,3)= x}}}
That's the same thing.
{{{x = log(6,1/18)}}}