Question 81886
move all values to one side then you get
{{{5a^2-33a-14=0}}} then use quadratic formula, which is {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
in your case {{{a=5}}}{{{ b=-33}}}{{{ c=-14}}}
so substitute these values into quadratic formula
{{{x = (33 +- sqrt( 1089+4*5*14 ))/(2*5) }}} 
{{{x = (33 +- 37)/(10) }}}
{{{x = 7 }}} or {{{x=-4/10=-2/5}}}