Question 960110
{{{ log( 3,x ) = c }}}
{{{ log( 3,b ) = 2c }}}
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Add the equations
{{{ log( 3,x ) + log( 3,b ) = 3c }}}
{{{ log( 3, b*x ) = 3c }}}
I can say:
{{{ 3^(3c) = b*x }}}
{{{ ( 3^3)^c = b*x }}}
{{{ b*x = 27^c }}}
{{{ x = 27^c / b }}} answer
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check:
{{{ log( 3,x ) = c }}}
{{{ 3^c = x }}}
{{{ 3^c = 27^c / b }}}
{{{ 3^c = ( 3^3)^c / b }}}
{{{ 3^c = ( 3^c)^3 / b }}}
{{{ b = ( 3^c )^2 }}}
{{{ b = 3^(2c) }}}
and this gives me:
{{{ log( 3, b ) = 2c }}}
OK