Question 959940
 equilateral triangle is increasing at a rate of sqrt(3) cm/min. find the rate at which its area increasing when its edge is 12 cm long.
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Area = b*h/2
h = b*sqrt(3)/2
Area = b^2*sqrt(3)/2
dA/dt = b*sqrt(3)*db/dt
= 12*sqrt(3)*sqrt(3) = 36 sq cm/minute