Question 959865
{{{y=x/(x+2)}}}
Interchange x and y and solve for the new y, that's the inverse.
{{{x=y/(y+2)}}}
{{{x(y+2)=y}}}
{{{xy+2x=y}}}
{{{xy-y=-2x}}}
{{{y(x-1)=-2x}}}
{{{y=(-2x)/(x-1)}}}
{{{f^(-1)(x)=(-2x)/(x-1)}}}