Question 959768
{{{ln(y) = ln((ln x)^(cos(4x)))}}}
{{{ln(y) = cos(4x)*ln((ln(x))))}}}
So then differentiating,
{{{(dy/dx)/y=cos(4x)*(1/(x*ln(x)))+ln(ln(x))*(-4sin(4x)))}}}
{{{dy/dx=y(cos(4x)/(x*ln(x))-4sin(4x)*ln(ln(x))))}}}
{{{dy/dx=(ln x)^cos(4x)*(cos(4x)/(x*ln(x))-4sin(4x)*ln(ln(x))))}}}