Question 959791
{{{A*B=14}}}
{{{A=3+2B}}}
Substituting,
{{{(3+2B)B=14}}}
{{{2B^2+3B-14=0}}}
{{{(B-2)(2B+7)=0}}}
Two solutions:
{{{B-2=0}}}
{{{B=2}}}
Then,
{{{2A=14}}}
{{{A=7}}}
and
{{{2B+7=0}}}
{{{2B=-7}}}
{{{B=-7/2}}}
Then,
{{{A(-7/2)=14}}}
{{{A=-28/7}}}
{{{A=-4}}}