Question 959765

inside square: side a has an area of {{{A[s]=a^2}}}

from one right-angle triangle with  hypotenuse a, and legs each {{{14in}}} we have

{{{a^2=14^2+14^2}}}
{{{a^2=196+196}}}
{{{a^2=392}}}

{{{A[inside-square]=a^2=392}}}

then the area should be deducted from the area of the circle with radius r=14

{{{A[circle]=r^2*pi}}}  

{{{A[circle]=14^2*(22/7)}}}  

{{{A[circle]=196*(22/7)}}}  

{{{A[circle]=196*3.142857142857143}}}  

{{{A[circle]=616}}}

shaded area is the difference between area of the

{{{A[shaded]=A[circle]-A[inside-square]}}}

{{{A[shaded]=616-392}}}

{{{A[shaded]=224in^2}}}................shaded area


unshaded area is the difference between area of the large square whose {{{2*14=28in}}} side is  and shaded area

the large square area {{{A=(28)^2}}}=>{{{A=784in^2}}}


unshaded area will be

{{{A[unshaded]=784-224}}}

{{{A[unshaded]=560in^2}}}