Question 959613
First off, the vertical asymptotes are {{{x=5}}} and {{{x=-5}}}.
Now for horizontal, divide the numerator and denominator by the highest term of either.
{{{(x)/(x^2-25)=(x/x^2)/((x^2-25)/x^2)}}}
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{{{(x)/(x^2-25)=(1/x)/(1-25/x^2)}}}
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Now take the limit as {{{x}}} goes to {{{infinity}}},
{{{(x/x^2)/((x^2-25)/x^2)=(0)/(1-0)}}}
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{{{(x/x^2)/((x^2-25)/x^2)=(0)/(1)}}}
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{{{(x/x^2)/((x^2-25)/x^2)=highlight(0)}}}
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{{{graph(300,300,-20,20,-3,3,x/(x^2-25))}}}