Question 959514
f(x)=x-2, g(x)= -3x^2 +15x-1, and h(x)= square root x-4
(f+h)=(x-2)+sqrt(x-4)
(f+h)(29)=(29-2)+sqrt(29-4)=27+sqrt(25)=27+5=32
(f+h)(29)=32

(f-g)=(x-2)-(-3x^2 +15x-1)=x-2+3x^2-15x+1=3x^2-14x-1
(f-g)(-5)=3(-5)^2-14(-5)-1=3(25)+70-1=75+70-1=145-1=144
(f-g)(-5)=144

(f+g)=(x-2)+(-3x^2 +15x-1)=x-2-3x^2 +15x-1=-3x^2+16x-3
(f+g)(x) = -3x^2+16x-3

f(x)=2x-3, and g(x)=3x^2-2x-1
(f of g)(-1)=f{g(-1)}=f{3(-1)^2-2(-1)-1}=f{3+2-1}=f(4)=2(4)-3=8-3=5

(f of f)(x)=f{f(x)}=f{2x-3}=2(2x-3)-3=4x-6-3=4x-9

(f of g)(x)=f{g(x)}=f{3x^2-2x-1}=2(3x^2-2x-1)-3=6x^2-4x-2