Question 959349
P=210
LET X BE THE SHORTEST SIDE.
LET X+50 BE THE SECOND SIDE.
LET 2X BE THE THIRD SIDE.
210=X+X+50+2X
210=4X+50
210-50=4X
160=4X
X=160/4
X=40 FOR THE SHORTEST SIDE.
40=50=90 FOR TH SECOND SIDE.
2*40=80 FOR THE THIRD SIDE.
PROOF:
210=40+80+80
210=210