Question 959335
n,n+2,and n+4 are consecutive odd integers
{{{sqrt(n+(n+2)+(n+4))+3=12}}} Subtract 3 from each side.
{{{sqrt(3n+6)=9}}} Square each side.
{{{3n+6=81}}} Subtract 6 from each side.
{{{3n=75}}} Divide each side by 3.
{{{n=25}}} ANSWER 1: The first odd number is 25
{{{n+2=25+2}}}={{{27}}} ANSWER 2: The second number is 27.
{{{N+4=25+4}}}={{{29}}} ANSWER 3: The third number is 29.
CHECK:
{{{sqrt(25+27+29)+3=12}}}
{{{sqrt(81)+3=12}}}
{{{9+3=12}}}
{{{12=12}}}