Question 959238
Triangles AED and CDF are right triangles with legs 4 in and 8 in,
so each has area (1/2)(4in)(8in)=16 square inches.
The small triangle EBF is a isosceles right triangle with legs 4 inches,
so has an area of (1/2)(4in)(4in)=8 square inches.
The total area of the square is (8in)(8in)=64 square inches.
The area of square square ABCD is the sum of the four triangles, 
so the area of triangle DEF = Area ABCD - Area AED - Area CDF - Area EBF
Area DEF={{{64in^2-16in^2-16in^2-8in^2=64in^2-40in^2}}}={{{24in^2}}}
ANSWER: The area of triangle DEF is 24 square inches.