Question 959233
The uncut portion of the square=8in-2(2in)=8in-4in=4inches
The length of diagonals is hypotenuse of right triangle with legs=2 inches:
The four diagonal cuts={{{sqrt(2^2+2^2)=sqrt(2*4)}}}={{{2sqrt(2)}}}
There are four slanted corners and four uncut portions so:
{{{Perimeter=4(2sqrt(2)in)+4(4in)}}}={{{8sqrt(2)in+16in}}}={{{11.3in+16in=27.3in}}}
ANSWER: The perimeter of the irregular octagon is 27.3 inches.