Question 959225


{{{V = pi*r^2*h}}}

given:

the diameter {{{13in}}} => then radius is {{{(13/2)in}}}
and 
volume is {{{V=102(3.14)in^3}}}

{{{102(3.14)in^3 = (3.14)*((13/2)in)^2*h}}}


{{{102cross((3.14))in^cross(3)^1 = cross((3.14))*((13/2)^2cross(in^2))*h}}}


{{{102in =(169/4)*h}}}


{{{102in*4 =169*h}}}


{{{408in/ 169=h}}}


{{{h=2.4142in}}}