Question 959203
{{{2=y+3}}}
{{{y=-1}}}
and
{{{4x-3=2y}}}
{{{y=(4x-3)/2}}}
{{{y=2x-3/2}}}
.
.

{{{drawing(300,300,-5,5,-5,5,grid(1),graph(300,300,-5,5,-5,5,-1,(4x-3)/2))}}}
You can't solve this graphically because the intersection doesn't land on one of the grid points so you'd be guessing.
But you can notice that the one line is {{{y=-1}}} and substitute into the other,
{{{4x-3=2(-1)}}}
{{{4x-3=-2}}}
{{{4x=1}}}
{{{x=1/4}}}
So the solution is (1/4,-1).
{{{drawing(300,300,-5,5,-5,5,circle(1/4,-1,0.2),grid(1),graph(300,300,-5,5,-5,5,-1,(4x-3)/2))}}}