Question 959201
-4a squared b to the sixth over two a to the fifth b to the fourth.
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-4a^2*b^6/[2a^5*b^4]
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= (-4/2)(a^2/a^5)(b^6/b^4)
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= -2(1/a^3)(b^2/1)
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= -2b^2/a^3
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Cheers,
Stan H.
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