Question 959170
y=x^(ln(x))
ln(y)=ln(x^(ln(x))
ln(y)=ln(x)ln(x)
implicit differentiation+product rule yields
(1/y)y'=(1/x)ln(x)+(1/x)ln(x)
(1/y)y'=(2/x)ln(x)
y'=(2/x)yln(x)
=(2yln(x))/x