Question 959160
{{{e^(x)-8e^(-x)=7}}}


{{{(e^(x)-8e^(-x))e^x=7*e^x}}}


{{{e^(2x)-8=7e^x}}}


{{{e^(2x)-7e^x-8=0}}}

Still not finished solving, but the equation is in quadratic form, and you can solve for {{{e^x}}}.