Question 959155

Consider the function f(x)=-2x^2-8x+2 Find the Vertex.
<pre>{{{f(x) = - 2x^2 - 8x + 2}}}
x-coordinate of the vertex is at: {{{x = - b/(2a)}}}
{{{x = - - 8/(2 * - 2)}}}
{{{x = 8/(- 4)}}}, or {{{x = - 2}}}

{{{f(x) = - 2x^2 - 8x + 2}}}
{{{f(- 2) = - 2(- 2)^2 - 8(- 2) + 2}}} ------- Substituting - 2 for x 
{{{f(- 2) = - 2(4) + 16 + 2}}}
{{{f(- 2) = - 8 + 16 + 2}}}
{{{f(- 2) = 10}}}
Vertex is found at the coordinate point: ({{{highlight_green(- 2)}}}{{{","}}}{{{highlight_green(10)}}})