Question 959079
Let {{{ a }}} = pounds of other ingredient
Let {{{ b }}} = pounds of gravel
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(1) {{{ a/b = 3/1 }}}
(2) {{{ a + b = 184 }}}
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(1) {{{ a = 3b }}}
and
(2) {{{ 3b + b = 184 }}}
(2) {{{ 4b = 184 }}}
(2) {{{ b = 46 }}}
and
(1) {{{ a = 3b }}}
(1) {{{ a = 138 }}}
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There are 46 pounds of gravel
(1) {{{ a/b = 3/1 }}}
(1) {{{ 138/46 = 3/1 }}}
(1) {{{ 3/1 = 3/1 }}}
OK