Question 959061
solve log base 4 (log base 3 (log base 2 of X)) 
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Let y = log4[log3[log2(x)]]
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Then::
4^y = log[3[log2(x)]]
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And:
3^(4y) = log2(x)
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So, 2^(12y) = x
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Solve for "y":
12y = log(x)/log(2)
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Ans:: y = (1/12)[log2(x)]
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Cheers,
Stan H.
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