Question 959033


{{{log(64, 32) = x}}}....change the base to base {{{10}}}

{{{log(32)/log(64) = x}}}

{{{log(2^5)/log(2^6) = x}}}

{{{5log(2)/6log(2) = x}}}

{{{5cross(log(2))/6cross(log(2)) = x}}}

{{{x=5/6 }}}