Question 959020
Three points
(0,0)
(0,6)
(8,0)
Find the midpoint of the line from (0,6) to (8,0).
Find the average of the x and y values
{{{x[m]=(0+8)/2=4}}}
{{{y[m]=(6+0)/2=3}}}
So then the distance from (0,0) to (4,3) is the distance you need.
{{{D^2=4^2+3^2}}}
{{{D^2=16+9}}}
{{{D^2=25}}}
{{{D=5}}}