Question 958841
1.{{{y-4z=0}}}
2.{{{4x + 2y = 12}}}
3.{{{-x-2y+6z=-3}}} 
From 1,
{{{y=4z}}}
{{{z=y/4}}}
Substitute into eq. 3,
{{{-x-2y+6(y/4)=-3}}}
{{{-2x-4y+3y=-3}}}
4.{{{-2x-y=-3}}}
From eq. 2,
5.{{{2x+y=12}}}
Adding 4 and 5,
{{{-2x-y+2x=y=-3+12}}}
{{{0=9}}}
False, the system is inconsistent.
There is no solution.