Question 958894

e^(2x+1)= log100 i'm trying to convert to logarithmic form, can you please help me?
<pre>{{{e^(2x + 1) = log 100}}} ---- Exponential form
{{{e^(2x + 1) = 2}}} --------- Converting log 100 to 2
ln 2 = 2x + 1 ------ Logarithmic form
    0.693147 = 2x + 1
0.693147 – 1 = 2x
  - 0.306853 = 2x
{{{x = (- 0.306853)/2}}}, or {{{highlight_green(x = - 0.1534265)}}}