Question 958355
For: [0,2π)
Csc^2 theta - cot theta - 1=0
{{{(1/sin^2(x))-(cosx/sinx)-1=0}}}
lcd: sin^2(x)
{{{(1-cosxsinx)-sin^2(x)=0}}}
{{{(1-cosxsinx)-(1-cos^2(x))=0}}}
{{{(-cosxsinx)+cos^2(x))=0}}}
{{{-cosx(sinx-cosx)=0}}}
-cosx=0
x=π/2, 3π/2
or
sinx-cosx=0
sinx=cosx
x=π/4, 5π/4