Question 956227
log(y-1) = - log(y-9)
log(y-1) = -1* log(y-9)
{{{log(y-1) = log((y-9))^-1}}}
{{{log(y-1) = log(1/(y-9))}}}
{{{y - 1 = 1/(y-9)}}}
{{{(y - 1)/1 = 1/(y-9)}}}
{{{(y - 1)(y-9)=1}}}
{{{y^2-9y-y+9=1}}}
{{{y^2-10y+9=1}}}
{{{y^2-10y+8=0}}}
{{{y = 5 + sqrt(17)}}}
Notice that {{{y = 5 - sqrt(17)}}}
will not work since this would make the value of y-9 in log(y-9) negative.