Question 958207
n=first integer; n+4=second integer
{{{(n)(n+4)=96}}}
{{{n^2+4n=96}}}
{{{n^2+4n-96=0}}}
{{{(n+12)(n-8)=0}}}
{{{n+12=0}}} or {{{n-8=0}}}
{{{n=-12}}} or {{{n=8}}} ANSWER 1: The first integer is 8.
n+4=8+4=12 ANSWER 2: The second integer is 12.