Question 81733
4x – 4y = –4
y = 2x + 0


Since the second equation is in the form y =___, it will be convenient to substitute this back into the first equation!


4x - 4y = -4
4x-4(2x) = -4
4x - 8x = -4
-4x = -4
x=1


Now, substitute this into either equation.  The easiest was is to use the y = __ equation.


y=2x
y=2(1)
y=2


The solution is (1,2).


Check in the OTHER equation:
4x-4y =-4
4(1)-4(2)=-4
4-8=-4  It checks!!


R^2 at SCC