Question 958171
Need to know how to solve ln(x/3+1)+ln(1/x)=2
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Adding logs --> multiply
{{{ln((x/3 + 1)/x) = 2}}}
{{{ln((x+3)/3x) = 2}}}
{{{((x+3)/3x) = e^2}}}
{{{x+3 = 3e^2*x}}}
{{{3 = 3e^2*x -x = x*(3e^2 - 1)}}}
{{{x = 3/(3e^2 - 1)}}}