Question 81732
x^-2-9x^-1+18=0


Change the negative exponents to fractions:
{{{1/(x^2) -9(1/x) +18 = 0}}}


Then multiply both sides of the equation by the LCD, which is {{{ x^2}}}:

{{{x^2*(1/(x^2)) -x^2*(9(1/x))  +x^2* 18 = x^2*0}}}
{{{1 -9x + 18x^2 = 0}}}
{{{18x^2 -9x+1=0}}}


This factors into 
{{{ (6x-1)(3x-1) =0}}}


First solution:
6x-1=0
6x=1
x= 1/6


Second solution:
3x-1=0
3x=1
x=1/3


R^2 at SCC