<PRE><B>Question 958102</B>
10x-20y=50 
26x+ay=130
If the two equations are equivalent, there are infinite solutions.
Divide the coefficient of x in first equation by coefficient in second: 10/26=2.6
Divide constant in first by constant in second: 50/130=2.6
They are the same, so use this factor to determine coefficient of y
(2.6)(20)=-52 
This makes the second equation:
26x+(-52)y=130 so a=-52 and both equations represent the same line, so there are infinite solutions.
ANSWER: The exceptional value of a is (-52).


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