Question 958056

There are two different formulas that you can use to find the {{{axis}}} of {{{symmetry}}}. 

One formula works when the parabola's equation is in {{{vertex}}}{{{ form}}} and the other works when the parabola's equation is in {{{standard}}}{{{ form}}}.

If your equation is in vertex form, then the axis of symmetry is:
{{{x= h}}} in the general vertex form equation {{{y = (x-h)^2 + k}}}

If your equation is in standard form, then the formula for the axis of symmetry is:
{{{x = -b/2a}}} from the general standard form equation {{{y = ax^2+bx + c}}}


your equation is in vertex form,the axis of symmetry is {{{x= h}}}

{{{y=-3(x-4)^2}}}=>{{{h=4}}}

so, the axis of symmetry is {{{x=4}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
line(4,-10,4,10),
 graph( 600, 600, -10, 10, -10, 10, -3(x-4)^2)) }}}