Question 957809
log2(x) + log(x-7) = 3 doesn't have a solution as far as i can see.


i couldn't solve it algebraically, but i could solve it graphically.


the solution is x = 794.40479.


when x = 794.40479, the graph of y = logx(2) + log(x-7) is equal to 3.


it will then intersect with the line of y = 3.


logx(2) is the same as log(2) / log(x), so the equation that was graphed was y = log(2)/log(x) + log(x-7)


log without a base is assumed to be a base of 10 by convention.


here's the graph.


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