Question 957556


let the larger  number be {{{x}}} and   the smaller number {{{y}}}

if the larger  number be {{{x}}} is 1 less than twice the smaller number {{{y}}}, we have

{{{x=2y-1}}}

expression for smaller number minus the larger number: 

{{{y-x}}}

{{{y-(2y-1)}}}

{{{y-2y+1}}}

{{{-y+1}}}

or
{{{1-y}}}