Question 957511
solve for x
2x^3+3x^2-8x=12
2x^3+3x^2-8x-12=0
x^2(2x+3)-4(2x+3)=0
(2x+3)(x^2-4)=0
(2x+3)(x+2)(x-2)=0
x=-3/2,-2, or 2