Question 957478
The term number {{{n}}} for 0 3 8 15 24 35 is
{{{T[n]=n^2-1}}} :
{{{T[1]=1^2-1=1-1=0}}} ,
{{{T[2]=2^2-1=4-1=3}}} ,
{{{T[3]=3^2-1=9-1=8}}} ,
{{{T[4]=4^2-1=16-1=15}}} ,
and so on,
The term number {{{n}}} for 1 1/2 1/4 1/8 1/16..... is
{{{T[n]}}}={{{1/(2^(n-1))}}} , or {{{T[n]=(1/2)^(n-1)}}} :
{{{T[1]}}}={{{1/(2^(1-1))=1/(2^0)=1/1=1}}} ,
{{{T[2]}}}={{{1/2^1=1/2}}} ,
{{{T[3]}}}={{{1/2^2=1/4}}} ,
{{{T[4]}}}={{{1/2^3=1/8}}} , and so on.