<PRE><B>Question 957316</B>
As written, this problem results in fractional coins.
Q=quarters; D=dimes
Q=1.25D
$0.10D+$0.25Q=$5.20 Substitute for Q.
$0.10D+$0.25(1.25D)=$5.20
$0.10D+$0.3125D=$5.20
$0.4125D=$5.20
D=12.6 ANSWER 1: She has 12.6 dimes
Q=1.25D=1.25(12.6)=15.8 ANSWER 2: She has 15.75 quarters.
CHECK:
$0.10D+$0.25Q=$5.20
$0.10(12.6)+$0.25(15.75)=$5.20
$1.26+$3.94=$5.20
$5.20=$5.20</PRE>