Question 957033
Factor out the common term 4x^2. You do so by erasing the 4x^2 terms to get



4x^2(a + b) + 4x^2(a - b)
<s>4x^2</s>(a + b) + <s>4x^2</s>(a - b)
(a+b)+(a-b)
(a+a)+(b-b)
2a+0b
2a


Therefore, we have 2a when we erase the 4x^2 terms. Now we reintroduce the 4x^2 back in to get 4x^2*2a


So, 4x^2(a + b) + 4x^2(a - b) factors to 4x^2*2a and that turns into 8a*x^2


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