Question 956933
{{{f(x)=2x(x-4)^2}}} Look at the squared operation, {{{(x-4)^2}}}. This is the same as (x-4)(x-4), since the square of a number equals the number times itself. Now we have: 
{{{2x(x-4)(x-4)}}} Let's follow F.O.I.L. to get rid of the parenthesis:
{{{x*x-4x-4x+16 = x^2-8x+16}}} So we now have:
{{{2x(x^2+8x+16)}}}. Here we have: {{{2x*x^2= 2x^3}}} and {{{2x*8x= 16x^2}}} and {{{2x*16= 32x}}}:
{{{2x^3-16x^2+32x}}}This is your answer.