Question 956892
Let the four odd integers be,
{{{N-2}}},{{{N}}}, {{{N+2}}}, and {{{N+4}}}
So then,
{{{(N-2)+3(N+4)+5=89}}}
{{{N-2+3N+12+5=89}}}
{{{4N+15=89}}}
{{{4N=74}}}
{{{N=37/2}}}
The solution should be an integer. 
Please check your problem set up and repost a corrected problem.