Question 956786
{{{2/(r-5) + 3/(2r+1) = 22/((2r+1)(r-5))}}}
{{{(2(2r+1))/((r-5)(2r+1)) + (3(r-5))/((2r+1)(r-5)) = 22/((2r+1)(r-5))}}}
{{{(2(2r+1) + 3(r-5))/((2r+1)(r-5)) = 22/((2r+1)(r-5))}}}
{{{2(2r+1)+3(r-5)=22}}}
{{{4r+2+3r-15=22}}}
{{{7r-13=22}}}
{{{7r=35}}}
{{{r=5}}}
However, in eliminating the denominators we assumed that {{{r-5<>0}}} and {{{2r+1<>0}}} to avoid division by zero. 
So {{{r=5}}} is not a possible solution.
No solution.