Question 956934
{{{5}}},{{{X}}},{{{39}}}
By definition, 
{{{X/5=k}}}
{{{39/X=k}}}
So then,
{{{X/5=39/X}}}
{{{X^2=5*39}}}
{{{X^2=195}}}
{{{X=sqrt(195)}}}
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{{{5}}},{{{sqrt(195)}}},{{{39}}}