Question 956807
{{{Ax=b}}}
{{{A=(matrix(2,2,1,-2,2,5))}}}
{{{x=(matrix(2,1,x,y))}}}
{{{b=(matrix(2,1,0,9))}}}
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{{{x=A^(-1)b}}}
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{{{abs(A)=1(5)-2(-2)=5+4=9}}}
{{{A^(-1)=(1/9)*(matrix(2,2,5,2,-2,1))}}}
So then,
{{{x=(1/9)*(matrix(2,2,5,2,-2,1))*(matrix(2,1,0,9))}}}
{{{x=(matrix(2,1,2,1))}}}