Question 956906
{{{(14xyz^5)/(4x^2y^3z^4)=(7/2)x^(1-2)y^(1-3)z^(5-4)}}}
{{{(14xyz^5)/(4x^2y^3z^4)=(7/2)x^(-1)y^(-2)z^(1)}}}
{{{(14xyz^5)/(4x^2y^3z^4)=(7z)/(2xy^2)}}}